(3x+1)/4=(2x-1)/5

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Solution for (3x+1)/4=(2x-1)/5 equation: 



(3x+1)/4=(2x-1)/5

We move all terms to the left:

(3x+1)/4-((2x-1)/5)=0

We calculate fractions


3x/()+(-((2x-1)*4)/()=0



We calculate terms in parentheses: +(-((2x-1)*4)/(), so:

-((2x-1)*4)/(

We multiply all the terms by the denominator


-((2x-1)*4)



We calculate terms in parentheses: -((2x-1)*4), so:

(2x-1)*4

We multiply parentheses

8x-4

Back to the equation:

-(8x-4)



We get rid of parentheses

-8x+4

Back to the equation:

+(-8x+4)



We get rid of parentheses

3x/()-8x+4=0

We multiply all the terms by the denominator


3x-8x*()+4*()=0

We add all the numbers together, and all the variables

3x-8x*()=0

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