(3x+1)/6=(2x-3)/3

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Solution for (3x+1)/6=(2x-3)/3 equation: 



(3x+1)/6=(2x-3)/3

We move all terms to the left:

(3x+1)/6-((2x-3)/3)=0

We calculate fractions


3x/()+(-((2x-3)*6)/()=0



We calculate terms in parentheses: +(-((2x-3)*6)/(), so:

-((2x-3)*6)/(

We multiply all the terms by the denominator


-((2x-3)*6)



We calculate terms in parentheses: -((2x-3)*6), so:

(2x-3)*6

We multiply parentheses

12x-18

Back to the equation:

-(12x-18)



We get rid of parentheses

-12x+18

Back to the equation:

+(-12x+18)



We get rid of parentheses

3x/()-12x+18=0

We multiply all the terms by the denominator


3x-12x*()+18*()=0

We add all the numbers together, and all the variables

3x-12x*()=0

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