(3x+1)2=12

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Solution for (3x+1)2=12 equation: 



(3x+1)2=12

We move all terms to the left:

(3x+1)2-(12)=0

We multiply parentheses

6x+2-12=0

We add all the numbers together, and all the variables

6x-10=0

We move all terms containing x to the left, all other terms to the right

6x=10

x=10/6

x=1+2/3

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