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(3x+1)=(2x+2)
We move all terms to the left:
(3x+1)-((2x+2))=0
We get rid of parentheses
3x-((2x+2))+1=0
We calculate terms in parentheses: -((2x+2)), so:We get rid of parentheses
(2x+2)
We get rid of parentheses
2x+2
Back to the equation:
-(2x+2)
3x-2x-2+1=0
We add all the numbers together, and all the variables
x-1=0
We move all terms containing x to the left, all other terms to the right
x=1
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