(3x+1)=(8x+7)=

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Solution for (3x+1)=(8x+7)= equation: 



(3x+1)=(8x+7)=

We move all terms to the left:

(3x+1)-((8x+7))=0

We get rid of parentheses

3x-((8x+7))+1=0



We calculate terms in parentheses: -((8x+7)), so:

(8x+7)

We get rid of parentheses

8x+7

Back to the equation:

-(8x+7)



We get rid of parentheses

3x-8x-7+1=0

We add all the numbers together, and all the variables

-5x-6=0

We move all terms containing x to the left, all other terms to the right

-5x=6

x=6/-5

x=-1+1/5

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