(3x+1)=(x+17)

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Solution for (3x+1)=(x+17) equation: 



(3x+1)=(x+17)

We move all terms to the left:

(3x+1)-((x+17))=0

We get rid of parentheses

3x-((x+17))+1=0



We calculate terms in parentheses: -((x+17)), so:

(x+17)

We get rid of parentheses

x+17

Back to the equation:

-(x+17)



We get rid of parentheses

3x-x-17+1=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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