(3x+1)=2(x+6)

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Solution for (3x+1)=2(x+6) equation: 



(3x+1)=2(x+6)

We move all terms to the left:

(3x+1)-(2(x+6))=0

We get rid of parentheses

3x-(2(x+6))+1=0



We calculate terms in parentheses: -(2(x+6)), so:

2(x+6)

We multiply parentheses

2x+12

Back to the equation:

-(2x+12)



We get rid of parentheses

3x-2x-12+1=0

We add all the numbers together, and all the variables

x-11=0

We move all terms containing x to the left, all other terms to the right

x=11

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