(3x+1)=5(x-2)+7

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Solution for (3x+1)=5(x-2)+7 equation: 



(3x+1)=5(x-2)+7

We move all terms to the left:

(3x+1)-(5(x-2)+7)=0

We get rid of parentheses

3x-(5(x-2)+7)+1=0



We calculate terms in parentheses: -(5(x-2)+7), so:

5(x-2)+7

We multiply parentheses

5x-10+7

We add all the numbers together, and all the variables

5x-3

Back to the equation:

-(5x-3)



We get rid of parentheses

3x-5x+3+1=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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