(3x+1)x=60

Solution for (3x+1)x=60 equation:

(3x+1)x=60

We move all terms to the left:

(3x+1)x-(60)=0

We multiply parentheses

3x^2+x-60=0

a = 3; b = 1; c = -60;
Δ = b2-4ac
Δ = 12-4·3·(-60)
Δ = 721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{721}}{2*3}=\frac{-1-\sqrt{721}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{721}}{2*3}=\frac{-1+\sqrt{721}}{6}
$