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(3x+10)(5x-2)=0
We multiply parentheses ..
(+15x^2-6x+50x-20)=0
We get rid of parentheses
15x^2-6x+50x-20=0
We add all the numbers together, and all the variables
15x^2+44x-20=0
a = 15; b = 44; c = -20;
Δ = b2-4ac
Δ = 442-4·15·(-20)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-56}{2*15}=\frac{-100}{30} =-3+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+56}{2*15}=\frac{12}{30} =2/5 $
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