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(3x+10)(6x-28)+36=180
We move all terms to the left:
(3x+10)(6x-28)+36-(180)=0
We add all the numbers together, and all the variables
(3x+10)(6x-28)-144=0
We multiply parentheses ..
(+18x^2-84x+60x-280)-144=0
We get rid of parentheses
18x^2-84x+60x-280-144=0
We add all the numbers together, and all the variables
18x^2-24x-424=0
a = 18; b = -24; c = -424;
Δ = b2-4ac
Δ = -242-4·18·(-424)
Δ = 31104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{31104}=\sqrt{5184*6}=\sqrt{5184}*\sqrt{6}=72\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-72\sqrt{6}}{2*18}=\frac{24-72\sqrt{6}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+72\sqrt{6}}{2*18}=\frac{24+72\sqrt{6}}{36} $
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