(3x+10)+(9x-9)+(3x-16)=180

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Solution for (3x+10)+(9x-9)+(3x-16)=180 equation:



(3x+10)+(9x-9)+(3x-16)=180
We move all terms to the left:
(3x+10)+(9x-9)+(3x-16)-(180)=0
We get rid of parentheses
3x+9x+3x+10-9-16-180=0
We add all the numbers together, and all the variables
15x-195=0
We move all terms containing x to the left, all other terms to the right
15x=195
x=195/15
x=13

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