(3x+10)+50+(x-8)=180

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Solution for (3x+10)+50+(x-8)=180 equation: 



(3x+10)+50+(x-8)=180

We move all terms to the left:

(3x+10)+50+(x-8)-(180)=0

We add all the numbers together, and all the variables

(3x+10)+(x-8)-130=0

We get rid of parentheses

3x+x+10-8-130=0

We add all the numbers together, and all the variables

4x-128=0

We move all terms containing x to the left, all other terms to the right

4x=128

x=128/4

x=32

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