(3x+10)+7x=50)=120

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Solution for (3x+10)+7x=50)=120 equation:



(3x+10)+7x=50)=120
We move all terms to the left:
(3x+10)+7x-(50))=0
We add all the numbers together, and all the variables
7x+(3x+10)=0
We get rid of parentheses
7x+3x+10=0
We add all the numbers together, and all the variables
10x+10=0
We move all terms containing x to the left, all other terms to the right
10x=-10
x=-10/10
x=-1

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