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(3x+10)=(2x)
We move all terms to the left:
(3x+10)-((2x))=0
determiningTheFunctionDomain (3x+10)-2x=0
We add all the numbers together, and all the variables
-2x+(3x+10)=0
We get rid of parentheses
-2x+3x+10=0
We add all the numbers together, and all the variables
x+10=0
We move all terms containing x to the left, all other terms to the right
x=-10
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