(3x+10)=(2x+9)+(7x-15)

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Solution for (3x+10)=(2x+9)+(7x-15) equation: 



(3x+10)=(2x+9)+(7x-15)

We move all terms to the left:

(3x+10)-((2x+9)+(7x-15))=0

We get rid of parentheses

3x-((2x+9)+(7x-15))+10=0



We calculate terms in parentheses: -((2x+9)+(7x-15)), so:

(2x+9)+(7x-15)

We get rid of parentheses

2x+7x+9-15

We add all the numbers together, and all the variables

9x-6

Back to the equation:

-(9x-6)



We get rid of parentheses

3x-9x+6+10=0

We add all the numbers together, and all the variables

-6x+16=0

We move all terms containing x to the left, all other terms to the right

-6x=-16

x=-16/-6

x=2+2/3

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