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(3x+10)=(x-2)
We move all terms to the left:
(3x+10)-((x-2))=0
We get rid of parentheses
3x-((x-2))+10=0
We calculate terms in parentheses: -((x-2)), so:We get rid of parentheses
(x-2)
We get rid of parentheses
x-2
Back to the equation:
-(x-2)
3x-x+2+10=0
We add all the numbers together, and all the variables
2x+12=0
We move all terms containing x to the left, all other terms to the right
2x=-12
x=-12/2
x=-6
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