(3x+11)+(3x+11)=(9x-14)

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Solution for (3x+11)+(3x+11)=(9x-14) equation: 



(3x+11)+(3x+11)=(9x-14)

We move all terms to the left:

(3x+11)+(3x+11)-((9x-14))=0

We get rid of parentheses

3x+3x-((9x-14))+11+11=0



We calculate terms in parentheses: -((9x-14)), so:

(9x-14)

We get rid of parentheses

9x-14

Back to the equation:

-(9x-14)



We add all the numbers together, and all the variables

6x-(9x-14)+22=0

We get rid of parentheses

6x-9x+14+22=0

We add all the numbers together, and all the variables

-3x+36=0

We move all terms containing x to the left, all other terms to the right

-3x=-36

x=-36/-3

x=+12

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