(3x+11)+(7x-5)=(9x-16

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Solution for (3x+11)+(7x-5)=(9x-16 equation: 



(3x+11)+(7x-5)=(9x-16

We move all terms to the left:

(3x+11)+(7x-5)-((9x-16)=0

We get rid of parentheses

3x+7x-((9x-16)+11-5=0

We add all the numbers together, and all the variables

10x-((9x-16)+11-5=0

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