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(3x+11)+(7x-5)=(9x-16)
We move all terms to the left:
(3x+11)+(7x-5)-((9x-16))=0
We get rid of parentheses
3x+7x-((9x-16))+11-5=0
We calculate terms in parentheses: -((9x-16)), so:We add all the numbers together, and all the variables
(9x-16)
We get rid of parentheses
9x-16
Back to the equation:
-(9x-16)
10x-(9x-16)+6=0
We get rid of parentheses
10x-9x+16+6=0
We add all the numbers together, and all the variables
x+22=0
We move all terms containing x to the left, all other terms to the right
x=-22
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