(3x+11)+(7x-5)=(9x-16)

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Solution for (3x+11)+(7x-5)=(9x-16) equation: 



(3x+11)+(7x-5)=(9x-16)

We move all terms to the left:

(3x+11)+(7x-5)-((9x-16))=0

We get rid of parentheses

3x+7x-((9x-16))+11-5=0



We calculate terms in parentheses: -((9x-16)), so:

(9x-16)

We get rid of parentheses

9x-16

Back to the equation:

-(9x-16)



We add all the numbers together, and all the variables

10x-(9x-16)+6=0

We get rid of parentheses

10x-9x+16+6=0

We add all the numbers together, and all the variables

x+22=0

We move all terms containing x to the left, all other terms to the right

x=-22

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