(3x+112)=(5x+100)

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Solution for (3x+112)=(5x+100) equation: 



(3x+112)=(5x+100)

We move all terms to the left:

(3x+112)-((5x+100))=0

We get rid of parentheses

3x-((5x+100))+112=0



We calculate terms in parentheses: -((5x+100)), so:

(5x+100)

We get rid of parentheses

5x+100

Back to the equation:

-(5x+100)



We get rid of parentheses

3x-5x-100+112=0

We add all the numbers together, and all the variables

-2x+12=0

We move all terms containing x to the left, all other terms to the right

-2x=-12

x=-12/-2

x=+6

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