(3x+12)(8-2x)=0

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Solution for (3x+12)(8-2x)=0 equation: 


Simplifying
(3x + 12)(8 + -2x) = 0

Reorder the terms:
(12 + 3x)(8 + -2x) = 0

Multiply (12 + 3x) * (8 + -2x)
(12(8 + -2x) + 3x * (8 + -2x)) = 0
((8 * 12 + -2x * 12) + 3x * (8 + -2x)) = 0
((96 + -24x) + 3x * (8 + -2x)) = 0
(96 + -24x + (8 * 3x + -2x * 3x)) = 0
(96 + -24x + (24x + -6x2)) = 0

Combine like terms: -24x + 24x = 0
(96 + 0 + -6x2) = 0
(96 + -6x2) = 0

Solving
96 + -6x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-96' to each side of the equation.
96 + -96 + -6x2 = 0 + -96

Combine like terms: 96 + -96 = 0
0 + -6x2 = 0 + -96
-6x2 = 0 + -96

Combine like terms: 0 + -96 = -96
-6x2 = -96

Divide each side by '-6'.
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}

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