(3x+12)(x-1)=0

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Solution for (3x+12)(x-1)=0 equation:



(3x+12)(x-1)=0
We multiply parentheses ..
(+3x^2-3x+12x-12)=0
We get rid of parentheses
3x^2-3x+12x-12=0
We add all the numbers together, and all the variables
3x^2+9x-12=0
a = 3; b = 9; c = -12;
Δ = b2-4ac
Δ = 92-4·3·(-12)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-15}{2*3}=\frac{-24}{6} =-4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+15}{2*3}=\frac{6}{6} =1 $

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