(3x+12)+(2x+23)+(180-(6x+18))=180

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Solution for (3x+12)+(2x+23)+(180-(6x+18))=180 equation: 



(3x+12)+(2x+23)+(180-(6x+18))=180

We move all terms to the left:

(3x+12)+(2x+23)+(180-(6x+18))-(180)=0

We get rid of parentheses

3x+2x+(180-(6x+18))+12+23-180=0



We calculate terms in parentheses: +(180-(6x+18)), so:

180-(6x+18)

determiningTheFunctionDomain
-(6x+18)+180

We get rid of parentheses

-6x-18+180

We add all the numbers together, and all the variables

-6x+162

Back to the equation:

+(-6x+162)



We add all the numbers together, and all the variables

5x+(-6x+162)-145=0

We get rid of parentheses

5x-6x+162-145=0

We add all the numbers together, and all the variables

-1x+17=0

We move all terms containing x to the left, all other terms to the right

-x=-17

x=-17/-1

x=+17

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