(3x+12)+(2x+42)=180

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Solution for (3x+12)+(2x+42)=180 equation: 



(3x+12)+(2x+42)=180

We move all terms to the left:

(3x+12)+(2x+42)-(180)=0

We get rid of parentheses

3x+2x+12+42-180=0

We add all the numbers together, and all the variables

5x-126=0

We move all terms containing x to the left, all other terms to the right

5x=126

x=126/5

x=25+1/5

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