(3x+12)+7=3(x+4)-13

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Solution for (3x+12)+7=3(x+4)-13 equation: 



(3x+12)+7=3(x+4)-13

We move all terms to the left:

(3x+12)+7-(3(x+4)-13)=0

We get rid of parentheses

3x-(3(x+4)-13)+12+7=0



We calculate terms in parentheses: -(3(x+4)-13), so:

3(x+4)-13

We multiply parentheses

3x+12-13

We add all the numbers together, and all the variables

3x-1

Back to the equation:

-(3x-1)



We add all the numbers together, and all the variables

3x-(3x-1)+19=0

We get rid of parentheses

3x-3x+1+19=0

We add all the numbers together, and all the variables

20!=0

There is no solution for this equation

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