(3x+12)/((x-5)*(x+1))=0

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Solution for (3x+12)/((x-5)*(x+1))=0 equation: 



(3x+12)/((x-5)(x+1))=0



Domain of the equation: ((x-5)(x+1))!=0

x∈R



We multiply parentheses ..

(3x+12)/((+x^2+x-5x-5))=0

We multiply all the terms by the denominator


(3x+12)=0

We get rid of parentheses

3x+12=0

We move all terms containing x to the left, all other terms to the right

3x=-12

x=-12/3

x=-4

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