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(3x+12)/7=2x-3
We move all terms to the left:
(3x+12)/7-(2x-3)=0
We get rid of parentheses
(3x+12)/7-2x+3=0
We multiply all the terms by the denominator
(3x+12)-2x*7+3*7=0
We add all the numbers together, and all the variables
(3x+12)-2x*7+21=0
Wy multiply elements
(3x+12)-14x+21=0
We get rid of parentheses
3x-14x+12+21=0
We add all the numbers together, and all the variables
-11x+33=0
We move all terms containing x to the left, all other terms to the right
-11x=-33
x=-33/-11
x=+3
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