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(3x+12)/9=15
We move all terms to the left:
(3x+12)/9-(15)=0
We multiply all the terms by the denominator
(3x+12)-15*9=0
We add all the numbers together, and all the variables
(3x+12)-135=0
We get rid of parentheses
3x+12-135=0
We add all the numbers together, and all the variables
3x-123=0
We move all terms containing x to the left, all other terms to the right
3x=123
x=123/3
x=41
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