(3x+12)=(2x+40)

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Solution for (3x+12)=(2x+40) equation: 



(3x+12)=(2x+40)

We move all terms to the left:

(3x+12)-((2x+40))=0

We get rid of parentheses

3x-((2x+40))+12=0



We calculate terms in parentheses: -((2x+40)), so:

(2x+40)

We get rid of parentheses

2x+40

Back to the equation:

-(2x+40)



We get rid of parentheses

3x-2x-40+12=0

We add all the numbers together, and all the variables

x-28=0

We move all terms containing x to the left, all other terms to the right

x=28

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