(3x+12)=(8x-33)

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Solution for (3x+12)=(8x-33) equation: 



(3x+12)=(8x-33)

We move all terms to the left:

(3x+12)-((8x-33))=0

We get rid of parentheses

3x-((8x-33))+12=0



We calculate terms in parentheses: -((8x-33)), so:

(8x-33)

We get rid of parentheses

8x-33

Back to the equation:

-(8x-33)



We get rid of parentheses

3x-8x+33+12=0

We add all the numbers together, and all the variables

-5x+45=0

We move all terms containing x to the left, all other terms to the right

-5x=-45

x=-45/-5

x=+9

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