(3x+12)=(8x-78)

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Solution for (3x+12)=(8x-78) equation: 



(3x+12)=(8x-78)

We move all terms to the left:

(3x+12)-((8x-78))=0

We get rid of parentheses

3x-((8x-78))+12=0



We calculate terms in parentheses: -((8x-78)), so:

(8x-78)

We get rid of parentheses

8x-78

Back to the equation:

-(8x-78)



We get rid of parentheses

3x-8x+78+12=0

We add all the numbers together, and all the variables

-5x+90=0

We move all terms containing x to the left, all other terms to the right

-5x=-90

x=-90/-5

x=+18

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