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(3x+12)=(9x)
We move all terms to the left:
(3x+12)-((9x))=0
determiningTheFunctionDomain (3x+12)-9x=0
We add all the numbers together, and all the variables
-9x+(3x+12)=0
We get rid of parentheses
-9x+3x+12=0
We add all the numbers together, and all the variables
-6x+12=0
We move all terms containing x to the left, all other terms to the right
-6x=-12
x=-12/-6
x=+2
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