(3x+12)=129

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Solution for (3x+12)=129 equation: 



(3x+12)=129

We move all terms to the left:

(3x+12)-(129)=0

We get rid of parentheses

3x+12-129=0

We add all the numbers together, and all the variables

3x-117=0

We move all terms containing x to the left, all other terms to the right

3x=117

x=117/3

x=39

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