(3x+13)+(3x+18)=(7x+14)

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Solution for (3x+13)+(3x+18)=(7x+14) equation: 



(3x+13)+(3x+18)=(7x+14)

We move all terms to the left:

(3x+13)+(3x+18)-((7x+14))=0

We get rid of parentheses

3x+3x-((7x+14))+13+18=0



We calculate terms in parentheses: -((7x+14)), so:

(7x+14)

We get rid of parentheses

7x+14

Back to the equation:

-(7x+14)



We add all the numbers together, and all the variables

6x-(7x+14)+31=0

We get rid of parentheses

6x-7x-14+31=0

We add all the numbers together, and all the variables

-1x+17=0

We move all terms containing x to the left, all other terms to the right

-x=-17

x=-17/-1

x=+17

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