(3x+13)=(2x+2)+(9x-13)

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Solution for (3x+13)=(2x+2)+(9x-13) equation: 



(3x+13)=(2x+2)+(9x-13)

We move all terms to the left:

(3x+13)-((2x+2)+(9x-13))=0

We get rid of parentheses

3x-((2x+2)+(9x-13))+13=0



We calculate terms in parentheses: -((2x+2)+(9x-13)), so:

(2x+2)+(9x-13)

We get rid of parentheses

2x+9x+2-13

We add all the numbers together, and all the variables

11x-11

Back to the equation:

-(11x-11)



We get rid of parentheses

3x-11x+11+13=0

We add all the numbers together, and all the variables

-8x+24=0

We move all terms containing x to the left, all other terms to the right

-8x=-24

x=-24/-8

x=+3

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