(3x+13)=(6x-6)+(3x+13)

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Solution for (3x+13)=(6x-6)+(3x+13) equation: 



(3x+13)=(6x-6)+(3x+13)

We move all terms to the left:

(3x+13)-((6x-6)+(3x+13))=0

We get rid of parentheses

3x-((6x-6)+(3x+13))+13=0



We calculate terms in parentheses: -((6x-6)+(3x+13)), so:

(6x-6)+(3x+13)

We get rid of parentheses

6x+3x-6+13

We add all the numbers together, and all the variables

9x+7

Back to the equation:

-(9x+7)



We get rid of parentheses

3x-9x-7+13=0

We add all the numbers together, and all the variables

-6x+6=0

We move all terms containing x to the left, all other terms to the right

-6x=-6

x=-6/-6

x=1

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