(3x+13)=(9x-14)+(x+8)

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Solution for (3x+13)=(9x-14)+(x+8) equation: 



(3x+13)=(9x-14)+(x+8)

We move all terms to the left:

(3x+13)-((9x-14)+(x+8))=0

We get rid of parentheses

3x-((9x-14)+(x+8))+13=0



We calculate terms in parentheses: -((9x-14)+(x+8)), so:

(9x-14)+(x+8)

We get rid of parentheses

9x+x-14+8

We add all the numbers together, and all the variables

10x-6

Back to the equation:

-(10x-6)



We get rid of parentheses

3x-10x+6+13=0

We add all the numbers together, and all the variables

-7x+19=0

We move all terms containing x to the left, all other terms to the right

-7x=-19

x=-19/-7

x=2+5/7

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