(3x+15)=(2x+50)

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Solution for (3x+15)=(2x+50) equation: 



(3x+15)=(2x+50)

We move all terms to the left:

(3x+15)-((2x+50))=0

We get rid of parentheses

3x-((2x+50))+15=0



We calculate terms in parentheses: -((2x+50)), so:

(2x+50)

We get rid of parentheses

2x+50

Back to the equation:

-(2x+50)



We get rid of parentheses

3x-2x-50+15=0

We add all the numbers together, and all the variables

x-35=0

We move all terms containing x to the left, all other terms to the right

x=35

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