(3x+15+(11x-5))/2=47

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Solution for (3x+15+(11x-5))/2=47 equation: 



(3x+15+(11x-5))/2=47

We move all terms to the left:

(3x+15+(11x-5))/2-(47)=0

We multiply all the terms by the denominator


(3x+15+(11x-5))-47*2=0



We calculate terms in parentheses: +(3x+15+(11x-5)), so:

3x+15+(11x-5)

determiningTheFunctionDomain
3x+(11x-5)+15

We get rid of parentheses

3x+11x-5+15

We add all the numbers together, and all the variables

14x+10

Back to the equation:

+(14x+10)



We add all the numbers together, and all the variables

(14x+10)-94=0

We get rid of parentheses

14x+10-94=0

We add all the numbers together, and all the variables

14x-84=0

We move all terms containing x to the left, all other terms to the right

14x=84

x=84/14

x=6

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