(3x+16)+(2x+25)+(2x+8)+(4x-18)+(3x-7)=720

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Solution for (3x+16)+(2x+25)+(2x+8)+(4x-18)+(3x-7)=720 equation:



(3x+16)+(2x+25)+(2x+8)+(4x-18)+(3x-7)=720
We move all terms to the left:
(3x+16)+(2x+25)+(2x+8)+(4x-18)+(3x-7)-(720)=0
We get rid of parentheses
3x+2x+2x+4x+3x+16+25+8-18-7-720=0
We add all the numbers together, and all the variables
14x-696=0
We move all terms containing x to the left, all other terms to the right
14x=696
x=696/14
x=49+5/7

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