(3x+16)+(2x+25)+(2x+8)+(4x-18)+(3x-7)=720

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Solution for (3x+16)+(2x+25)+(2x+8)+(4x-18)+(3x-7)=720 equation: 



(3x+16)+(2x+25)+(2x+8)+(4x-18)+(3x-7)=720

We move all terms to the left:

(3x+16)+(2x+25)+(2x+8)+(4x-18)+(3x-7)-(720)=0

We get rid of parentheses

3x+2x+2x+4x+3x+16+25+8-18-7-720=0

We add all the numbers together, and all the variables

14x-696=0

We move all terms containing x to the left, all other terms to the right

14x=696

x=696/14

x=49+5/7

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