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(3x+16)=(2x+50)
We move all terms to the left:
(3x+16)-((2x+50))=0
We get rid of parentheses
3x-((2x+50))+16=0
We calculate terms in parentheses: -((2x+50)), so:We get rid of parentheses
(2x+50)
We get rid of parentheses
2x+50
Back to the equation:
-(2x+50)
3x-2x-50+16=0
We add all the numbers together, and all the variables
x-34=0
We move all terms containing x to the left, all other terms to the right
x=34
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