(3x+16)=(9x-19)+(2x+5)

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Solution for (3x+16)=(9x-19)+(2x+5) equation: 



(3x+16)=(9x-19)+(2x+5)

We move all terms to the left:

(3x+16)-((9x-19)+(2x+5))=0

We get rid of parentheses

3x-((9x-19)+(2x+5))+16=0



We calculate terms in parentheses: -((9x-19)+(2x+5)), so:

(9x-19)+(2x+5)

We get rid of parentheses

9x+2x-19+5

We add all the numbers together, and all the variables

11x-14

Back to the equation:

-(11x-14)



We get rid of parentheses

3x-11x+14+16=0

We add all the numbers together, and all the variables

-8x+30=0

We move all terms containing x to the left, all other terms to the right

-8x=-30

x=-30/-8

x=3+3/4

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