(3x+16+x+12=180.x)

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Solution for (3x+16+x+12=180.x) equation: 



(3x+16+x+12=180.x)

We move all terms to the left:

(3x+16+x+12-(180.x))=0

We add all the numbers together, and all the variables

(3x+16+x+12-(+180.x))=0



We calculate terms in parentheses: +(3x+16+x+12-(+180.x)), so:

3x+16+x+12-(+180.x)

determiningTheFunctionDomain
3x+x-(+180.x)+16+12

We add all the numbers together, and all the variables

4x-(+180.x)+28

We get rid of parentheses

4x-180.x+28

We add all the numbers together, and all the variables

-176x+28

Back to the equation:

+(-176x+28)



We get rid of parentheses

-176x+28=0

We move all terms containing x to the left, all other terms to the right

-176x=-28

x=-28/-176

x=7/44

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