(3x+17)+(10x-5)=(3x+2)

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Solution for (3x+17)+(10x-5)=(3x+2) equation: 



(3x+17)+(10x-5)=(3x+2)

We move all terms to the left:

(3x+17)+(10x-5)-((3x+2))=0

We get rid of parentheses

3x+10x-((3x+2))+17-5=0



We calculate terms in parentheses: -((3x+2)), so:

(3x+2)

We get rid of parentheses

3x+2

Back to the equation:

-(3x+2)



We add all the numbers together, and all the variables

13x-(3x+2)+12=0

We get rid of parentheses

13x-3x-2+12=0

We add all the numbers together, and all the variables

10x+10=0

We move all terms containing x to the left, all other terms to the right

10x=-10

x=-10/10

x=-1

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