(3x+17)=(2x-6)+(8x-7)

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Solution for (3x+17)=(2x-6)+(8x-7) equation: 



(3x+17)=(2x-6)+(8x-7)

We move all terms to the left:

(3x+17)-((2x-6)+(8x-7))=0

We get rid of parentheses

3x-((2x-6)+(8x-7))+17=0



We calculate terms in parentheses: -((2x-6)+(8x-7)), so:

(2x-6)+(8x-7)

We get rid of parentheses

2x+8x-6-7

We add all the numbers together, and all the variables

10x-13

Back to the equation:

-(10x-13)



We get rid of parentheses

3x-10x+13+17=0

We add all the numbers together, and all the variables

-7x+30=0

We move all terms containing x to the left, all other terms to the right

-7x=-30

x=-30/-7

x=4+2/7

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