(3x+19)+(3x+4)=(10x-1)

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Solution for (3x+19)+(3x+4)=(10x-1) equation: 



(3x+19)+(3x+4)=(10x-1)

We move all terms to the left:

(3x+19)+(3x+4)-((10x-1))=0

We get rid of parentheses

3x+3x-((10x-1))+19+4=0



We calculate terms in parentheses: -((10x-1)), so:

(10x-1)

We get rid of parentheses

10x-1

Back to the equation:

-(10x-1)



We add all the numbers together, and all the variables

6x-(10x-1)+23=0

We get rid of parentheses

6x-10x+1+23=0

We add all the numbers together, and all the variables

-4x+24=0

We move all terms containing x to the left, all other terms to the right

-4x=-24

x=-24/-4

x=+6

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