(3x+19)+(7x+5)=2x+8

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Solution for (3x+19)+(7x+5)=2x+8 equation: 



(3x+19)+(7x+5)=2x+8

We move all terms to the left:

(3x+19)+(7x+5)-(2x+8)=0

We get rid of parentheses

3x+7x-2x+19+5-8=0

We add all the numbers together, and all the variables

8x+16=0

We move all terms containing x to the left, all other terms to the right

8x=-16

x=-16/8

x=-2

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