(3x+19)=(3x+4)+(10x-1)

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Solution for (3x+19)=(3x+4)+(10x-1) equation:



(3x+19)=(3x+4)+(10x-1)
We move all terms to the left:
(3x+19)-((3x+4)+(10x-1))=0
We get rid of parentheses
3x-((3x+4)+(10x-1))+19=0
We calculate terms in parentheses: -((3x+4)+(10x-1)), so:
(3x+4)+(10x-1)
We get rid of parentheses
3x+10x+4-1
We add all the numbers together, and all the variables
13x+3
Back to the equation:
-(13x+3)
We get rid of parentheses
3x-13x-3+19=0
We add all the numbers together, and all the variables
-10x+16=0
We move all terms containing x to the left, all other terms to the right
-10x=-16
x=-16/-10
x=1+3/5

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