(3x+1=2x+12)

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Solution for \(3x+1=2x+12\) equation:



(3x+1=2x+12)
We move all terms to the left:
(3x+1-(2x+12))=0
We calculate terms in parentheses: +(3x+1-(2x+12)), so:
3x+1-(2x+12)
determiningTheFunctionDomain 3x-(2x+12)+1
We get rid of parentheses
3x-2x-12+1
We add all the numbers together, and all the variables
x-11
Back to the equation:
+(x-11)
We get rid of parentheses
x-11=0
We move all terms containing x to the left, all other terms to the right
x=11

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